## Thursday, September 23, 2010

### First relevant post

This post is more likely to not be relevant but whatever. So tonight I spent my night asking people on Omegle to solve this.

Only 2 out of the 30 or so people solved the problem. It's quite a simple Geometry problem, can you solve it?

1. Can you post the solution?

2. I could, but that wouldn't be much fun.

3. x = 26.87 to 2dp

4. Don't the ' - ' on each leg of the triangle mean they're of equal length?

It's been awhile for me since I did any geometry...

5. pythagorean theorem?

7. x=19. That angle is not marked as a right one, while all 3 sides are marked as of equal length.

8. exactly 19, since there all marked the same length, so we just assume the teacher cant draw for shit

9. the answer is X. it says right there.

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11. a^2+b^2=C^2
(19x19)+(19x19)
361+361=722
sqrt of 722 is 26.87

12. pythagorean theorum obviously

13. x=19

Nice visual angle, bro.

14. It's definitely 19 if you think about it. Tempting to use Pythagoras' theorem, though!

15. i believe the answer is derp^7

16. 19. Very tricky indeed.

17. This blog kicks angle-side-side if you know what I mean.

18. @jacku
Wrong, its not necessarily a right triangle

Theyre all the same because of the hash marks, it indicates congruity.

19. MATH WTF do i look Asian